Bayes' theorem for two events states: P(A|B) equals what?

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Multiple Choice

Bayes' theorem for two events states: P(A|B) equals what?

Explanation:
Bayes' theorem updates what we believe about A after seeing B. It says the probability of A given B equals the probability of B given A times the prior probability of A, all divided by the probability of B: P(A|B) = P(B|A) P(A) / P(B). The numerator P(B|A)P(A) combines how likely B is if A is true with how likely A was to begin with, and dividing by P(B) normalizes this to a real probability by accounting for how common B is overall. In other words, we adjust our initial belief about A by how B supports A, then scale by how likely B is in the population. Note that P(A ∩ B) = P(A|B) P(B) is a true identity but it doesn’t give the Bayes update in terms of P(B|A) and P(A); it’s a different relationship. The other forms either misplace terms or imply independence when that isn’t guaranteed.

Bayes' theorem updates what we believe about A after seeing B. It says the probability of A given B equals the probability of B given A times the prior probability of A, all divided by the probability of B: P(A|B) = P(B|A) P(A) / P(B). The numerator P(B|A)P(A) combines how likely B is if A is true with how likely A was to begin with, and dividing by P(B) normalizes this to a real probability by accounting for how common B is overall. In other words, we adjust our initial belief about A by how B supports A, then scale by how likely B is in the population.

Note that P(A ∩ B) = P(A|B) P(B) is a true identity but it doesn’t give the Bayes update in terms of P(B|A) and P(A); it’s a different relationship. The other forms either misplace terms or imply independence when that isn’t guaranteed.

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